Question

A projectile fired at 5 m/s from a gun. If the horizontal component of the initial velocity is equal to 4 m/s. What is the value of the vertical component?

Answer 1

`the \: value \: of \: the \: vertical \: component \to : \\ (v_v) = 3m {s}^( - 1) \\`

Explanation:

`let \: the \: velocity \: be \to \: v \\let \: the \: horizontal \: component \: be \to \: v_h \\ let \: the \: vertical \: component \: be \to \: v_v \\ applying \: the \: pythagorean \: rule \: of \: vectors \to : \\ {v}^(2) = {v_v}^(2) + {v_h}^(2) \\ {v_v}^(2) = {v}^(2) - {v_h}^(2) \\ {v_v}^(2) = {5}^(2) - {4}^(2) \\ v_v = √((25 - 16)) \\ v_v = √(9) \\ \boxed{ v_v = 3 {ms}^( - 1) }`