A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displaceme…

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asked Aug 2, 2018 123k views

2 Answers

Romit Kumar · Answer 1 · 2018-08-07T22:40:31+0000

Step-by-step explanation:

It is given that,

Height of the mountain, h = 235 m

A skier descends a mountain at an angle of 35º to the horizontal,
$\theta=35^(\circ)$

We need to find the horizontal and vertical components of the skier's displacement.

Horizontal component,
$x=h\ cos\theta$

$x=235\ cos(35)=192.5\ m$

Vertical component,
$y=h\ sin\theta$

$y=235\ sin(35)=134.79\ m$

Hence, this is the required solution.