asked 219k views
1 vote
Which part of an atom participates in the reaction shown below?

U235 + n → Xe134 + Sr100 + 2n
A) Nuclei
B) Protons
C) Valence electrons
D) Inner shell electrons

asked
User Peenut
by
8.5k points

2 Answers

5 votes

the answer is nuclei

answered
User Remon Van Vliet
by
8.1k points
6 votes

Answer: Option (A) is the correct answer.

Step-by-step explanation:

A reaction in which nucleus of an atom and a subatomic particle like proton or neutron collide or when any two nuclei combine together then it results in the formation of a new nucleus that is different from its parent nuclei.

For example,
^(235)U + n \rightarrow ^(134)Xe + ^(100)Sr + 2n

Here, nucleus of Uranium collides with a neutron resulting in formation of a Xenon and Strontium nucleus along with two neutrons.

Therefore, we can conclude that nuclei of an atom participates in the given reaction.

answered
User Steven Luu
by
9.4k points
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