Question

A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on blue and the second spin lands on gray.

Answer 1

The probability of that is 6/25

Answer 2

Answer: 0.24

Explanation:

We use the formula ,

`\text{Probability}=\frac{\text{favorable outcomes}}{\text{total outcomes}}`

Given : A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue.

Event 1 : spin lands on blue

`P(E_1)=(6)/(10)`

Event 2 : spin lands on gray

`P(E_2)=(4)/(10)`

Since both the events are independent of each other , then the probability that the first spin lands on blue and the second spin lands on gray will be :-

`P(E_1)* P(E_2)\\\\=(6)/(10)*(4)/(10)=0.24`

Hence, the probability that the first spin lands on blue and the second spin lands on gray = 0.24