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How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?
asked 230k views
5 votes
How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

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User Mikebertiean
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8.6k points

2 Answers

5 votes

8.1 mol KCI

This would be the answer.

answered
User SomeKittens
by
8.1k points
2 votes
5.4 M = moles of solute / 1.50 L

Multiply both sides by 1.50 L to isolate moles of solute on the right.

8.1 mol = moles of solute


answered
User Charles Holbrow
by
8.6k points
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