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Oil change the shape of the distribution of the time required to get an oil change at a 10-minute oil-change facility is unknown. however, records indicate that the mean time for an oil change is 11.4 minutes, and the standard deviation for oil-change time is 3.2 minutes.

(a to compute probabilities regarding the sample mean using the normal model, what size sample would be required?
(b what is the probability that a random sample of n = 40 oil changes results in a sample mean time of less than
10 minutes?
(c suppose the manager agrees to pay each employee a $50 bonus if they meet a certain goal. on a typical saturday, the oil-change facility will perform 40 oil changes between 10
a.m. and 12 p.m. treating this as a random sample, what mean oil-change time would there be a 10% chance of being at or below? this will be the goal established by the manager.

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User Daya
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2 Answers

1 vote

Final answer:

To compute probabilities regarding the sample mean using the normal model, a sample size of at least 30 is typically considered sufficient. To find the probability that a sample mean time is less than 10 minutes, use the Z-score formula. To find the mean oil-change time with a 10% probability, find the corresponding Z-score.

Step-by-step explanation:

(a) To compute probabilities regarding the sample mean using the normal model, you would need a sample size that is large enough to satisfy the Central Limit Theorem. According to the Central Limit Theorem, a sample size of at least 30 is typically considered sufficient for the normal distribution approximation.

(b) To find the probability that a random sample of n = 40 oil changes results in a sample mean time of less than 10 minutes, you can use the Z-score formula. First, calculate the Z-score using the formula Z = (X - μ) / (σ / √n), where X is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size. Once you have the Z-score, you can use a Z-table or a calculator to find the corresponding probability.

(c) To find the mean oil-change time that would have a 10% chance of being at or below, you need to find the Z-score that corresponds to a 10% probability in the left tail of the standard normal distribution. Once you have the Z-score, you can use the formula Z = (X - μ) / (σ / √n) to solve for X, the mean oil-change time.

answered
User Kontur
by
8.1k points
5 votes
B I think I really hope this helps
answered
User Her
by
8.2k points

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