Question

27.What is the logarithmic form of the equation e2x ≈ 1732?

ln 1732 = 2x
log2x1732 = e
2 logxe = 1732
ln 2x = 1732

Answer 1

To get rid of exponential, you need to put ln on the other side.

So, to get 2x you need to write ln 1732

Answer is the first one.

Answer 2

Logarithm form of
`e^(2x)=1732` is
`2x=\ln 1732`

Explanation:

Given equation
`e^(2x)=1732`

We need to write given exponential form into logarithm

using log property to write in logarithm

`a^m=x`

`m\ln a=\ln x`

`e^(2x)=1732`

Apply ln both sides

`2x\ln e=\ln 1732`

`2x=\ln 1732` ∴ln e = 1

Thus, Logarithm form of
`e^(2x)=1732` is
`2x=\ln 1732`