Question

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?

Answer 1

Hope this helps you!

Answer 2

181.82N

Step-by-step explanation:

We have the following:

Coefficient of kinetic friction:
`\mu=0.22`

Kinetic frictional force:
`f=40N`

and we have a formula that relates these two quantities:

`f=\mu N`

where
`N` is the normal force. So since the normal force is what we are asked for, we clear for N in the last equation:

`N=(f)/(\mu)`

and substituting all the known values:

`N=(40N)/(0.22) =181.818N`

The normal force has a value of 181.82N