Question

Use the information to calculate deltaGrxn at 298 K. 3H2(g) +N2(g) 2NH3(g) deltaHrxn = -92.38 deltaSrxn =-198.2 J/K deltaGrxn = ___kJ

Answer 1

first part = - 2453.1

second part = - 33.3

Step-by-step explanation:

edg 22

Answer 2

-33.3 kj

Step-by-step explanation: