Register

A shopkeeper blends3 types of tea A,B,C in a ratio 6:4:7. if the mass ofv tea C in the mixture is 28kg find the difference in the mass of other 2 of teas

A shopkeeper blends3 types of tea A,B,C in a ratio 6:4:7. if the mass ofv tea C in the mixture is 28kg find the difference in the mass of other 2 of teas
asked 157k views
2 votes
a shopkeeper blends3 types of tea A,B,C in a ratio 6:4:7. if the mass ofv tea C in the mixture is 28kg find the difference in the mass of other 2 of teas

asked
User Jason Li
by
7.5k points

2 Answers

5 votes
The answer to the question is 8kg
answered
User Redlab
by
8.4k points
4 votes
A would be 6/7 x 28kg = 24 kg B would be 4/7 x 28kg = 16 kg so the difference of the masses is 24 - 16 = 8kg
answered
User Clark Bao
by
8.3k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!