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If m∠2 = x, m∠3 = 40, and m∠4 = 5x + 14, what is m∠1? 80 21 121 61

If m∠2 = x, m∠3 = 40, and m∠4 = 5x + 14, what is m∠1? 80 21 121 61
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If m∠2 = x, m∠3 = 40, and m∠4 = 5x + 14, what is m∠1?

80
21
121
61

If m∠2 = x, m∠3 = 40, and m∠4 = 5x + 14, what is m∠1? 80 21 121 61-example-1
asked
User Wade Tandy
by
8.4k points

2 Answers

4 votes
The answer is 61, x+40+5x+14=180, so x equals 21. 5(21)+14 ends up equaling 119, so 180-119 equals 1
answered
User Adr
by
8.3k points
5 votes
Hope this helps you.
If m∠2 = x, m∠3 = 40, and m∠4 = 5x + 14, what is m∠1? 80 21 121 61-example-1
answered
User Dylan Wheeler
by
8.5k points
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