Question

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules?

(Planck's constant is 6.626 × 10-34 joule seconds)

Answer 1

E=hf
3.611x10⁻¹⁵ = (6.63x10⁻³⁴)(f)
f=
`(3.611x10 x^(-15) )/(6.63x10 x^(-34) )`
f=5.45x10¹⁸