Question

Which function has a vertex at the origin

A) f(x)= (x+4)^2
B) f(x)= x(x-4)
C) f(x)= (x-4)(x+4)
D) f(x)= x^2

Answer 1

Explanation:

i love helping people so the answer is D

Answer 2

D) f(x)= x^2

prove :
f'(x) = 2x ;
f'(x) = 0 at, x= 0