Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width

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asked Aug 7, 2018 143k views

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Shab · Answer 1 · 2018-08-12T16:47:05+0000

2L + 2W = 610L = 2W + 20 Substitute the second equation into the first: 2(2W + 20) + 2W = 610 Solve for W. 4W + 40 + 2W = 6106W = 570W = 95 Use the second equation to solve for L

Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width

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