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Find the roots for 6x^2-x-1=0

asked
User MayeulC
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8.5k points

1 Answer

5 votes
Use the quadratic formula
x = [--1 +- sq root(1 (-4*6*-1))] / 2*6
x = [ 1 + sqroot (25)] / 12
x1 = 6 /12 = .5

x = [ 1 - sqroot (25)] / 12
x = (1 -5) / 12
x = -4 / 12
x2 = -.33333333333333

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