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2 votes
How to solve 8x^3-27=0

asked
User Jeem
by
7.4k points

2 Answers

5 votes
8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2
answered
User Potr Czachur
by
7.5k points
0 votes
Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)
answered
User Gok Demir
by
7.4k points

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