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5 votes
a car leaves a town by traveling at 40 mph and two hours later,a second car left the same time in the same road,and the same directions at 60 mph,the question is in how many hours the second car passes the first car????

1 Answer

4 votes

\bf \begin{array}{ccccllll} &distance&rate&time(hrs)\\ &\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\ \textit{first car}&d&40&t\\ \textit{second car}&d&60&t+2 \end{array} \\ \quad \\\\\\ d=d\implies (40)(t)=(60)(t+2)

"t", is the time the first car has travelled when reaching "d" distance,
whatever that is, at that point, the second car is passing it
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User Tashera
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