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What is the solution set of 7x^2+3x=0

2 Answers

1 vote
take the common 'x' out,

7x^2 +3x = 0
x (7x+3) = 0

so x = 0 or 7x+3 = 0
x=0 or 7x = -3
x=0 or x = -3/7

so the solutions are 0,-3/7.
answered
User Claytog
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7.8k points
0 votes

Answer:

x = 0 or x = -3/7

Explanation:

The equation is a second order polynnomial and would therefore have two solutions for x.

The solution of the set can be expressed as:


=7*x^2+3*x=0

The x is a common term in the expression so we can write is as:


=x*(7*x+3)=0

Where the expression is equal to zero the first solution of x is 0: x=0

The second part (7x+3) is also equal to zero and therefore:


7*x+3=0

After simplification x = -3/7

The solution of the set is x=0 or x=-3/7

Substituting either in the left hand side of the equation will make the whole equation equal to zero.

answered
User Apostlion
by
8.2k points

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