Question

Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's bedroom is 1.2 inches wide and 1.6 inches long.

What are the actual measurements of Harper's bedroom?


Harper's bedroom is ____ feet wide and ____ feet long

Answer 1

so 30 ft is equal to 4 Inc on scale !
therefore 1.2 on scale will be (30/4)×1.2= 9 ft wide !!

6 Inc on scale is equal to 45 feet on actual
so 1.6 will be (45/6)×1.6= 12 ft long


so answer is 9 ft wide and 12 ft long !!

Answer 2

Harper's bedroom is
`9` feet wide and
`12` feet long

Explanation:

step 1

Find the scale of the drawing

we know that

Harper's house is
`30` feet wide and
`45` feet long. On a scale drawing, the house is
`4` inches wide and
`6` inches long

The scale is equal to

`(4)/(30)(inches)/(feet) =(6)/(45)(inches)/(feet)=(1)/(7.5)(inches)/(feet)`

step 2

Find the the actual measurements of Harper's bedroom

we know that

Harper's bedroom on a scale drawing is
`1.2` inches wide and
`1.6` inches long

The scale drawing is
`(1)/(7.5)(inch)/(feet)`

therefore

To obtain the actual measurements multiply the measurements on a scale drawing by
`7.5`

so

`wide=1.2*7.5=9\ ft`

`long=1.6*7.5=12\ ft`