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When 3.5 mol Al react with 12.5 mol HCl, what is the limiting reactant and how many moles of H2 can be formed? 2Al + 6HCl yields 2AlCl3 + 3H2
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When 3.5 mol Al react with 12.5 mol HCl, what is the limiting reactant and how many moles of H2 can be formed? 2Al + 6HCl yields 2AlCl3 + 3H2
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Feb 8, 2018
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When 3.5 mol Al react with 12.5 mol HCl, what is the limiting reactant and how many moles of H2 can be formed? 2Al + 6HCl yields 2AlCl3 + 3H2
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Ankit Tyagi
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Hope it cleared your doubt.
Roger Medeiros
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Feb 14, 2018
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Roger Medeiros
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