Question

In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O

Answer 1

0.6 moles is the answer

Answer 2

Answer : The number of moles of
`Ca(OH)_2` required are, 0.6 mole.

Explanation : Given,

Moles of HI = 1.2 moles

The given balanced chemical reaction is,

`2HI+Ca(OH)_2\rightarrow CaI_2+2H_2O`

From the balanced chemical reaction, we conclude that

As, 2 moles of
`HI` react with 1 mole of
`Ca(OH)_2`

So, 1.2 moles of
`HI` react with
`(1.2)/(2)=0.6` mole of
`Ca(OH)_2`

Therefore, the number of moles of
`Ca(OH)_2` required are, 0.6 mole.