Question

A balloon holds 20.0 L of helium at 10 degree Celsius. If the temperature doubles, and the pressure does not change, what will be the new volume of the balloon? Using Charles's Law

Please help!

Answer 1

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 2 x 20.0/ 1

V2 = 40 L