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(15−4i)(6−3i)=a+bi In the equation above, a and b are real numbers and i=−1‾‾‾√. What is the value of a? a=

(15−4i)(6−3i)=a+bi In the equation above, a and b are real numbers and i=−1‾‾‾√. What is the value of a? a=
asked 13.1k views
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(15−4i)(6−3i)=a+bi

In the equation above, a and b are real numbers and i=−1‾‾‾√. What is the value of a?

a=

asked
User Ziteng Chen
by
7.7k points

2 Answers

5 votes
The answer is
a = 15 + 6
= 21
answered
User Alex Averbuch
by
8.1k points
5 votes

Answer:

14

Explanation:

15 -4=11

6-3=3

then a minus ND minus it makes a plus the 11+3=14

answered
User Tedtoal
by
8.7k points
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