In order to solve the problem, we should know the heat capacity of silver. Which is equal to 0.240 J/g C 
The formula: H = mCpT 
 Where h is the energy applied 
 M is the mass 
 Cp is the specific heat 
 T is the change in temperature 
125 J = ( 29.3 g ) ( 0.240 J/g C) 
T Solve for T 
T = 17.78 degree C increase