Question

Determine the type and number of solutions of x^2-8x+16=0

Answer 1

type?
anyway, what 2 numbers multiply to get 16 and add to get -8
-4 and -4
(x-4)(x-4)=0
(x-4)²=0

set to zeo
x-4=0
x=4

there is 1 soltuion repeated twice (x=4)

Answer 2

This would factor to (x-4)(x-4)=0

The discriminant would be b^2-4ac___64-4*1*16=0

The factors show x=4,x=4; a double root and the discriminant shows 0 which is also 1 real rational zero