asked 152k views
0 votes
At a local baseball game there are 3 hot dog vendors. collectively the vendors sold 1,700 hot dogs. if vendor a sold 456, vendor b sold 607, and vendor c sold 637, what percentage of the total did each vendor sell? (round to the nearest percent.) a) 26 percent, 40 percent, 44 percent b) 45 percent, 37 percent, 18 percent c) 27 percent, 36 percent, 37 percent d) 30 percent, 35 percent, 35 percent

asked
User Aryan
by
8.5k points

2 Answers

6 votes
456×100÷1700≈26.8
607×100÷1700≈35.7
637×100÷1700≈37.4

So the answer is C)27%, 36%, 37%.

Hope this helped!
answered
User Sventechie
by
7.9k points
3 votes

Answer:

c) 27 percent, 36 percent, 37 percent

Explanation:

Given,

Hot dogs sold by,

Vendor a = 456

Vendor b = 607

Vendor c = 637,

Total hot dogs = 1700,

Thus, the percentage of the hot dogs sold by a =
\frac{\text{Hot dog sold by a}}{\text{Total hot dogs}}* 100


=(456)/(1700)* 100


=(456)/(17)

= 26.82%

27%

Similarly,

Percentage of the hot dogs sold by a


=(607)/(1700)* 100


=(607)/(17)

= 35.71%

36%

Percentage of the hot dogs sold by a


=(637)/(1700)* 100


=(637)/(17)

= 37.47%

37%

Hence, OPTION c) is correct.

answered
User Nick Krasnov
by
9.0k points
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