Question

Use the graph below to answer the question that follows:

What are the amplitude, period, and midline of the function?

Amplitude: 4; period: 2π; midline: y = −1
Amplitude: 8; period: 2π; midline: y = 1
Amplitude: 8; period: π; midline: y = −1
Amplitude: 4; period: π; midline: y = 1

Answer 1

Answer should be
Amplitude:4 (total height of the graph divide 2)
period: 2π ( one full oscillation, 5π/2-π/2)
midline: y= -1 ( total height uses 8 boxes in
graph....midline would be equal
boxes on both side)

Answer 2

Amplitude : 4

Period: 2π

Mid-line: y=-1

A is correct

Explanation:

We are given graph of periodic function.

We need to find amplitude, period and midline of the function.

From graph:

Maximum value = 3

Minimum value = -5

`\text{Mid-Line }=(Max+Min)/(2)`

`\text{Mid-Line }=(3-5)/(2)=-1`

The mid-line equation, y=-1

Amplitude: Distance between mid-line and maximum value

Amplitude = 3-(-1) = 4

The amplitude of given graph is 4

Period: It is time when graph repeat their path.

In the given graph repeat their in 2π of interval.

The period of graph is 2π