Question

A local am radio station broadcasts at a frequency of 764 khz. calculate the energy of the frequency at which it is broadcasting. energy = kj/photon

Answer 1

The frequency of the emitted radio waves is:

`f=764 kHz = 7.64 \cdot 10^5 Hz`

The energy of a photon is given by:

`E=hf`
where h is the Planck constant and f is the photon frequency. Using the frequency given by the problem, we can find the energy of each photon of this radiation:

`E=hf=(6.6 \cdot 10^(-34) Js)(7.64 \cdot 10^5 Hz)=5.04 \cdot 10^(-28) J=5.04 \cdot 10^(-31) kJ`