Question

When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 298 k?

Answer 1

4342 K

Step-by-step explanation:

Answer 2

Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant

`(P1)/(T1) = (P2)/(T2)`
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting the values in the equation

`(1100 bar)/(T) = (75.5 bar)/(298 K)`
T = 4342 K
initial temperature was 4342 K