Question

How many liters of chlorine gas, at standard temperature and pressure, will react with 15.5 grams of potassium metal? Show all of the work used to solve this problem.

2K + Cl2 —> 2KCl

Answer 1

V = 6.8 L

Step-by-step explanation:

2K(s) + Cl2(g) --> 2KCl(s)

25.6g.....?L

25.6g K x (1 mol K / 39.1g K) x (1 mol Cl2 / 2 mol K) = 0.3274 mol Cl2

PV = nRT

V = nRT / P

V = 0.3274 mol x 0.08206 Latm/molK x 278K / 1.1 atm

V = 6.8 L

The pressure (1.1 atm), which is expressed to two significant digits, limits the precision of the answer to two significant digits.

Answer 2

I think about 6.2 liters