Question

You compared the two functions below. f(x) = 1.2t      g(x) = 1.2t-5

What did subtracting 5 in the exponent do to the function? Check all that apply.
A. It shifts the graph of f left 5 units.
B. It shifts the graph of f right 5 units.
C. It multiplies all the y-values by 5.
D. It divides all the y-values by 5.
E. It multiplies all the y-values by 1.25.
F. It divides all the y-values by 1.25.

Answer 1

the second and the last are the correct ones

Answer 2

B. It shifts the graph of f right 5 units.

F. It divides all the y-values by 1.25.

Explanation:

Let me revise your two functions:

f(x) =
`1.2^(t)`

g(x) =
`1.2^(t-5)`

So g(x) is the transformed function of f(x), as we know that

• if we subtract anything from x or t (independent variable), the graph will move right.

• if we add anything from x or t (independent variable), the graph will move left.

In this situation, we subtract 5 from it, so the graph of f right 5 units.

However, it also affect to the value of y, I will rewrite g(x)

g(x) =
`(1.2^(t) )/(1.2^(5) )` =
`1.2^(t)` *
`(1)/(1.25^(5) )` =
`(1)/(1.25^(5) )` f(x)