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Rewrite the expression in simplest radical form. 108√

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\bf √(108)\qquad \begin{cases} 108=2\cdot 2\cdot 3\cdot 3\cdot 3\\ \qquad 2^2\cdot 3^2\cdot 3\\ \qquad (2\cdot 3)^2\cdot 3\\ \qquad 6^2\cdot 3\\ \end{cases}\implies √(6^2\cdot 3)\implies 6√(3)
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User Tarun Nagpal
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