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Find the center and radius of the circle with the given equation: (x + 3)2 + (y – 5)2 = 4

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\text{The equation in standard forn of the circle with radius r and a center}\\\text{in A(a; b) is}\ (x-a)^2+(y-b)^2=r^2}\\\\\text{therefore:}\\\\(x+3)^2+(y-5)^2=4\\\\center:(-3;\ 5);\ radius:r=\sqrt4=2
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User Albert Romkes
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