Question

Hey can you please help me posted picture of question

Answer 1

When the discriminant is lesser than zero then b. It has two complex solns

Answer 2

We have the following equation:
ax2 + bx + c = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
We have:
b2 - 4ac <0
Therefore the root is negative
Answer:
It has two complex solutions
option B