Question

Which is closest to the height of a cone that has a slant height of 16 inches and a radius of 6 inches?

Answer 1

`l \: = \sqrt{h ^(2) \: + \: r^2 }`

`h = \sqrt{l^(2) - {r}^(2) }`
Given
l (slant height) = 16 inches
r (radius) = 6 inches

`h = \sqrt{ {16}^(2) - {6}^(2) }`

`h = √(256 - 36)`

`h = √(220)`
h = 14.832 inches

Answer 2

Answer: 14.83 inches

Step-by-step explanation:

h² + 6² = 16²

h² = 16² - 6²

h² = 220

h = 14.83