Question

What could be the fourth quantum number for one of the electrons in the 4p energy sublevel of bromine?

Answer 1

Answer: 1

Step-by-step explanation:

Answer 2

Answer : The fourth quantum number for one of the electrons in the 4p energy sublevel of bromine is,
`m_s=+(1)/(2)\text{ or }-(1)/(2)`

Explanation :

There are 4 quantum numbers :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as
`m_l`. The value of this quantum number ranges from
`(-l\text{ to }+l)`. When l = 2, the value of
`m_l` will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as
`m_s` The value of this is
`+(1)/(2)` for upward spin and
`-(1)/(2)` for downward spin.

In the bromine atom the one electron in 4p energy sublevel,
`4p^1`.

Now we have to calculate the values of all the quantum numbers.

For
`4p^1` :

`n=4` (Because it is in 4rd shell)

`l=1` (Because it is in 'p' orbital)

`m_l=-1,0,1` (Because l = 1)

`m_s=+(1)/(2)\text{ or }-(1)/(2)` (Because of the sign convention)

Therefore, the fourth quantum number for one of the electrons in the 4p energy sublevel of bromine is,
`m_s=+(1)/(2)\text{ or }-(1)/(2)`