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If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50 M what is the volume of the new solution

If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50 M what is the volume of the new solution
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If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50 M what is the volume of the new solution

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User Rafael Delboni
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1 Answer

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The volume of the new solution is calculated using the formula below

M1V1 = M2V2
M1= 15.0 M
V1= 50.0 ml
M2=2.50 M
V2=?

V2=M1V1/V2

=50 ml x 15m/2.5 M =300 ML
answered
User Hans One
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