Question

Find the slope of the line containing the following two points 3/10,-5 and -1/5,-1/5

Answer 1

`\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ &&(~ (3)/(10) &,& -5~) &&(~ -(1)/(5) &,& -(1)/(5)~) \end{array}`


`\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-(1)/(5)-(-5)}{-(1)/(5)-(3)/(10)}\implies \cfrac{\stackrel{LCD~of~5}{-(1)/(5)+5}}{\stackrel{LCD~of~10}{-(1)/(5)-(3)/(10)}} \\\\\\ \cfrac{\quad (-1+25)/(5)\quad }{(-2-3)/(10)}\implies \cfrac{\quad (24)/(5)\quad }{(-5)/(10)}\implies \cfrac{24}{5}\cdot \cfrac{10}{-5}\implies \cfrac{24}{5}\cdot -2 \\\\\\ -\cfrac{48}{5}\implies -9(3)/(5)`