Question

The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?

Answer 1

x + 2x+7 + x- 12 = 131

Explanation:

i did the test

Answer 2

First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number),
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131