Question

Tara has two bags of marbles 6 red marbles, 5 blur marbles, and 4 green. the second bag contains 3 red marbles, 2 blue marbles, and 4 green marbles. tara will randomly select 1 marble from each bag. what is the probability that tara will select a blue marble from each bag

Answer 1

The probability of selecting a blue marble from each bag is 4/135.

Step-by-step explanation:

To find the probability of selecting a blue marble from each bag, we need to multiply the probabilities of selecting a blue marble from each bag separately. Let's denote the events as A (selecting a blue marble from the first bag) and B (selecting a blue marble from the second bag).

The probability of event A is calculated as the number of favorable outcomes (2 blue marbles) divided by the total number of possible outcomes -

(6+5+4 = 15 marbles in the first bag).

The probability of event B is calculated as the number of favorable outcomes (2 blue marbles) divided by the total number of possible outcomes -

(3+2+4 = 9 marbles in the second bag).

Therefore, the probability of selecting a blue marble from each bag is -

P(A) * P(B)

= (2/15) * (2/9)

= 4/135.

Answer 2

The correct answer is:

2/27

Explanation:

The two events, drawing a blue marble out of each bag, are independent. This means to find the probability of both occurring, we multiply them.

In the first bag, there are 5 blue marbles out of 15 total. This makes the probability 5/15, or 1/3.

In the second bag, there are 2 blue marbles out of 9 total. This makes the probability 2/9.

Together, the probability of both events happening are:

1/3(2/9) = 2/27