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A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag so that the probability of randomly …

A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag so that the probability of randomly …
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25 votes
A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag so that the probability of randomly joined a blue marble is 1/3?

asked
User Stephane Maarek
by
8.5k points

1 Answer

9 votes

Answer:

5 blue marbles

Explanation:

31/3 = about 10

15-10=5

answered
User MaxF
by
7.8k points
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