Question

50 POINTS!!! PLEASE HELP

Find the probability of x successes in n trials for the given probability of success p on each trial.

x = 2, n = 6, p = 0.7

Answer 1

The answer would be 0.0595.

Answer 2

The probability is 0.0595.

We find this using the formula

`_nC_x(p)^x(1-p)^(n-x) \\ \\=_6C_2{0.7)^2(1-0.7)^(6-2) \\ \\=_6C_2(0.7)^2(0.3)^4 \\ \\=15(0.7)^2(0.3)^4 = 0.0595`