Question

A bat hits a 0.150 kg baseball for 0.0880s. The balls velocity changes from 41.0 m/s left to 37.0 m/s right. How much force was applied to the ball? Unit= N

Answer 1

133

Step-by-step explanation:

Right answer

Answer 2

From Newton's second law of motion,

F=ma
Where, F = applied force, m = mass (=0.15 kg), a = acceleration.

a= Δv/t, Δv= Change in velocity, t = time
Therefore
a = (41-37)/0.088 = 45.45 m/s^2
Then,

F = 0.15*45.45 = 6.82 N