asked 111k views
2 votes
A 10-foot ladder is leaned against a wall. The angle between the base of the ladder and the ground measures 62°. How far up the wall does the ladder reach from the ground rounded to the nearest tenth?

asked
User Natke
by
8.0k points

1 Answer

5 votes
To solve this problem you must apply the proccedure shown below:

1. You have that:

- The10-foot ladder is leaned against a wall.
- The angle between the base of the ladder and the ground measures 62°.

2. Therefore, you have:

Sinα=opposite/hypotenuse

α=62°
opposite=x
hypotenuse=10

3. Therefore, when you clear "x", you obtain:

Sin(62°)=x/10
(10)(Sin(62°))=x
x=8.82

How far up the wall does the ladder reach from the ground rounded to the nearest tenth?

The answer is: 8.82 ft


answered
User Max Liashuk
by
8.0k points
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