Question

If the heat capacity of a ceramic cup is 0.820 j°c-1, how much heat is required to raise the temperature of the cup from 25.0°c to 50.0°c?

Answer 1

Step-by-step explanation:

Heat is equal to heat capacity multiplied by change in temperature.

Mathematically,
`Q = C * \Delta T`

where C = heat capacity

`\Delta T` = change in temperature

Therefore, calculate heat as follows.

`Q = C * \Delta T`

=
`0.820 j^(o)C * (50.0 - 25.0)^(o)C`

= 20.5 j

Thus, we can conclude that heat is required to raise the temperature of the cup is 20. 5 joules.

Answer 2

The heat required to raise the temperature of the cup from 25 c to 50 c is calculated as follows
Q (heat) = c x delta T
c = specific heat capacity = 0. 820 j/c
delta T = change in temperature ( 50 c- 25 c = 25c

= 0.820 j /c x 25 c = 20.5 j