Question

What is the [OH-]if the pH of a solution 10.62

Answer 1

The answer is [OH-]=4.169x10^-4

Step-by-step explanation:

Fill in the blank 4.169 and then negative 4.

Answer 2

As we know,

pH + pOH = 14
Or,
pOH = 14 - pH

Putting Value of pH,

pOH = 14 - 10.62

pOH = 3.38

pOH is converted into [OH⁻] as follow,

[OH⁻] = 10⁻pOH ∴ -pOH is in power, 10 means antilog
press shift and click log button
[OH⁻] = 10⁻³°³⁸

[OH⁻] = 0.0004168

[OH⁻] = 4.16 × 10⁻⁴