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Y=3x+8 12x−4y=−32 ​ How many solutions does this system have?

Y=3x+8 12x−4y=−32 ​ How many solutions does this system have?
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2 votes
Y=3x+8 12x−4y=−32 ​ How many solutions does this system have?

asked
User Ferschae Naej
by
8.7k points

1 Answer

5 votes
-3x+y = 8
12x-4y = -32

(-3x+y = 8) 4
12x-4y = -32

-12x+4y = 32
12x-4y = -32

0=0

Infinitely many solutions.
answered
User Manoj Kumar S
by
8.1k points
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