Question

Which of the following values of x satisfy the equation 3x^2-8x+4=0

Answer 1

`3x^2-8x+4=0\\\\\Delta=b^2-4ac=(-8)^2-4*3*4=64-48=16\\\\x_1=(-b+√(\Delta))/(2a)=(8-4)/(6)=(4)/(6)=(2)/(3)\\\\x_2=(-b-√(\Delta))/(2a)=(8+4)/(6)=(12)/(6)=2\\\\\boxed{S=\left\{(2)/(3);2\right\}}`

Answer 2

Hey there :)

3x² - 8x + 4 = 0

Divide into 2 groups

3x² - 6x - 2x + 4
3x ( x - 2 ) - 2 ( x - 2 ) = 0
↓ ↓
Factor out the GCF

x = 2
↑
( 3x - 2 )( x - 2 ) = 0
↓
x =
`(2)/(3)`


2 values satisfy x =
`(2)/(3) , 2`