Question

PLEASE HELP! Ordinary brass contains 61.6% copper, 2.9% lead, 0.2% tin, and 35.3% zinc. How many pounds of each metal would be in 160 lb. of brass?

Answer 1

There would be 98.56 lbs of copper, 4.64 lbs of lead, 0.32 lbs of tin, and 56.48 lbs of zinc.

61.6% = 0.616; 160(0.616)=98.56
2.9% = 0.029; 160(0.029) = 4.64
0.2% = 0.002; 160(0.002) = 0.32
35.3% = 0.353; 160(0.353) = 56.48

Answer 2

`\text{Amount of copper}=98.56\text{ lb}`

`\text{Amount of lead}=4.64\text{ lb}`

`\text{Amount of tin}=0.32\text{ lb}`

`\text{Amount of zinc}=56.48\text{ lb}`

Explanation:

We have been given that ordinary brass contains 61.6% copper, 2.9% lead, 0.2% tin, and 35.3% zinc.

The amount of each metal would be given percent of 160 pounds.

`\text{Amount of copper}=(61.6)/(100)* 160\text{ lb}`

`\text{Amount of copper}=0.616* 160\text{ lb}`

`\text{Amount of copper}=98.56\text{ lb}`

`\text{Amount of lead}=(2.9)/(100)* 160\text{ lb}`

`\text{Amount of lead}=0.029* 160\text{ lb}`

`\text{Amount of lead}=4.64\text{ lb}`

`\text{Amount of tin}=(0.2)/(100)* 160\text{ lb}`

`\text{Amount of tin}=0.002* 160\text{ lb}`

`\text{Amount of tin}=0.32\text{ lb}`

`\text{Amount of zinc}=(35.3)/(100)* 160\text{ lb}`

`\text{Amount of zinc}=0.353* 160\text{ lb}`

`\text{Amount of zinc}=56.48\text{ lb}`