Question

A mixture of gases with a pressure of 800 mmhg contains 10% oxygen and 90% nitrogen by volume. what is the partial pressure of the oxygen gas in the mixture?[

Answer 1

The partial pressure of the oxygen gas in the mixture is 80 mmHg.

Step-by-step explanation:

Total pressure of the gas mixture ,p = 800 mmHg

Percentage of oxygen gas = 10% = 0.10 =
`\chi_(O_2)`

Percentage of nitrogen gas = 90% = 0.90=
`\chi_(N_2)`

Partial pressure an individual gas in a mixture is given by Dalton's law of partial pressure:

`p_(O_2)=p* \chi_(O_2)=800 Hg * 0.10 =80 mmHg`

`p_(N_2)=p* \chi_(O_2)=800 Hg * 0.90 =720 mmHg`

The partial pressure of the oxygen gas in the mixture is 80 mmHg.

Answer 2

The partial pressure of the oxygen gas in the mixture is calculated is calculated as follows


total pressure of oxygen + nitrogen
the partial pressure of oxygen percentage of 0xygen / total percentage x total pressure
= 10/100x800= 80 mmHg